x^2+32x+13=0

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Solution for x^2+32x+13=0 equation:


Simplifying
x2 + 32x + 13 = 0

Reorder the terms:
13 + 32x + x2 = 0

Solving
13 + 32x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + 32x + -13 + x2 = 0 + -13

Reorder the terms:
13 + -13 + 32x + x2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + 32x + x2 = 0 + -13
32x + x2 = 0 + -13

Combine like terms: 0 + -13 = -13
32x + x2 = -13

The x term is 32x.  Take half its coefficient (16).
Square it (256) and add it to both sides.

Add '256' to each side of the equation.
32x + 256 + x2 = -13 + 256

Reorder the terms:
256 + 32x + x2 = -13 + 256

Combine like terms: -13 + 256 = 243
256 + 32x + x2 = 243

Factor a perfect square on the left side:
(x + 16)(x + 16) = 243

Calculate the square root of the right side: 15.588457268

Break this problem into two subproblems by setting 
(x + 16) equal to 15.588457268 and -15.588457268.

Subproblem 1

x + 16 = 15.588457268 Simplifying x + 16 = 15.588457268 Reorder the terms: 16 + x = 15.588457268 Solving 16 + x = 15.588457268 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = 15.588457268 + -16 Combine like terms: 16 + -16 = 0 0 + x = 15.588457268 + -16 x = 15.588457268 + -16 Combine like terms: 15.588457268 + -16 = -0.411542732 x = -0.411542732 Simplifying x = -0.411542732

Subproblem 2

x + 16 = -15.588457268 Simplifying x + 16 = -15.588457268 Reorder the terms: 16 + x = -15.588457268 Solving 16 + x = -15.588457268 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = -15.588457268 + -16 Combine like terms: 16 + -16 = 0 0 + x = -15.588457268 + -16 x = -15.588457268 + -16 Combine like terms: -15.588457268 + -16 = -31.588457268 x = -31.588457268 Simplifying x = -31.588457268

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-0.411542732, -31.588457268}

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